x^2+(1+x)=0

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Solution for x^2+(1+x)=0 equation: 



x^2+(1+x)=0

We add all the numbers together, and all the variables

x^2+(x+1)=0

We get rid of parentheses

x^2+x+1=0

a = 1; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·1·1
Δ = -3
Delta is less than zero, so there is no solution for the equation

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